Here are the answers to Saturday's CCNA and CCNP practice questions.

CCNA:

Short Answer: Convert the following binary string to a dotted decimal IP address.

00111100 00110101 00101010 01101010

Answer: 60.53.41.106


CCNP / BSCI:

There is a three-router DIS election on an Ethernet segment. The interface priorities are at their default. Which of the following is true?

A. The priority is 1 and the router with the highest MAC address will win.

B. The priority is zero and the router with the highest MAC address will win.

C. The priority is 64 and the router with the highest MAC address will win.

D. The priority is 128 and the router with the highest MAC address will win.

E. The priority is 1 and the router with the lowest MAC address will win.

F. The priority is zero and the router with the lowest MAC address will win.

G. The priority is 64 and the router with the lowest MAC address will win.

H. The priority is 128 and the router with the lowest MAC address will win.

Answer: C. On an Ethernet segment, the default priority is 64 and if there is a tie, the router with the highest MAC address will win. On Frame Relay, the router with the highest DLCI number will win.

CCNP / BCMSN:

What is the main purpose of IEEE 802.3ac?

A. Allows the switch to handle runt frames

B. Allows access ports to become trunks

C. Allows the maximum frame length to be extended

D. Allows VTP transparent mode to forward advertisements received from other switches

Answer: C. The IEEE 802.3ac standard allows the maximum frame length to be extended to 1522 bytes, which means the 4-byte dot1q header causes no transmission issues.


CCNP / BCRAN:

Short answer: Given a CIR of 128 KBPS and a time interval of 1/8th of a second, what is the Bc?

Answer: 16000. To arrive at the Bc (Committed Burst) value, multiply the CIR by the time interval.

In this case, that would be 128000 x .125, which equals 16000.


To your Cisco certification success,

Chris Bryant
CCIE #12933
www.thebryantadvantage.com