Thanks as always for sharing these posts via Google +1s, Twitter, Facebook, and more!  You're the best!

Time for your CCNA and CCENT practice exam for Thursday, October 31!


A quick reminder -- today's the last day to save 75% on any Udemy course -- including mine!  -- with the discount code DISCOVER 775.

So go browse my free and almost-free courses, and use that discount code to get 75% off any and every course!

CCNA And CCNP Video Boot Camps on Udemy



Let's get to today's exam!



1.   When configuring router-on-a-stick, where are IP addresses required?

A.  On the router's physical interfaces.

B.  On the router's logical interfaces.

C.  On the L3 switch's VLAN interfaces.

D.  On the L2 switch's VLAN interfaces.







2.  In a router-on-a-stick config, the host devices should use what as the default gateway?

A.  The VLAN 1 interface on the local switch.

B.  The router's physical interface.

C.  The L3 switch's VLAN interfaces.

D.  None of the above.







3.   Summarize the following routes.

10.1.0.0 /16
10.2.0.0 /16
10.3.0.0 /16
10.4.0.0 /16






4.   Short answer:  What interface-level command will change a Cisco router's Serial interface from its default encapsulation to the encap that allows you to choose between PAP and CHAP?
command.





Answer and explanations right after this brief, important message!


Earn your CCNA with my all-new CCNA 200-120 Video Boot Camp!

You get immediate access to my 27-hour course for just $44!

Join over 6500 students in the march to CCNA and CCNA exam success!



Join us right now by clicking this banner!





And now... the answers!

1.  "B". With ROAS, you're going to create subinterfaces on the router, and the IP addresses will be configured on those subinterfaces.


2.  "D".  The hosts should use the IP addresses on the subinterfaces as their default gateway.


3.   The summary is 10.0.0.0 /13, which can also be expressed as 10.0.0.0 255.248.0.0.

Going from left to right, the first two octets look like this:

10.1.0.0   00001010  00000001

10.2.0.0   00001010  00000010

10.3.0.0   00001010  00000011

10.4.0.0   00001010  00000100

The summary ends where the routes being summarized no longer have a bit in common.  That happens after 13 bits, where the top three routes have a 0 and the bottom route has a 1. 

That's your summary route, and the summary mask is the number of bits in common.  That's it!

4.  To switch from the default of HDLC to PPP, use the encapsulation ppp command. (On both ends of the connection, of course!)


Thanks for taking today's practice exam, and I'll see you on YouTube and Udemy!



Chris B.




Comments

Popular posts from this blog