Tuesday, July 30, 2013

And we're back --- again!  

My apologies for the lack of blog updates lately -- we've been running into some "issues" with our hosting friends that I believe have finally been resolved.   

So once again I'll be posting CCNA, CCENT, and CCNP links throughout the day, including a new practice exam.

See you later today!

Chris B.


Let's take a moment for a CCNA and CCNP Quick Quiz on IP Version 6, NAT, PAT, and more!

Question 1:

Which of the following do OSPFv2 and OSPFv3 have in common?  Choose all that apply.

A.   Sending of Hello packets for dynamic neighbor discovery.

B.   The SPF algorithm.

C.   The use of the router-id command to create the OSPF RID manually.

D.   The use of areas, the metric of "cost", and LSA exchange.

Question 2:    

OSPF v2 uses the multicast addresses and for important multicast functions.  What are the two counterpart addresses in OSPF v3?

No choices for this one!

Question 3:

In which of the following is it acceptable to use the IP address already in use on the NAT outside interface for address translation?

A.  Static NAT

B.  Dynamic NAT


D.  All of the above

Question 4:

What wildcard mask is represented by the word "any"?

Question 5:

Convert the hex value a4D to decimal.

Answers right after this quick, important message!

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OSPF Quick Quiz answers:

1.  First, we gotta know that OSPFv2 is the good ol' OSPF we're come to know and love with our IPv4 configurations, and OSPFv2 is simply OSPF for IPv6.

Next, we have to know that while there are important differences between the two versions, none of them were listed in this question.  

Both versions use Hello packets, dynamically discover neighbors, use the SPF algorithm, offer the router-id command for manual setting of the RID, and both use areas, cost, and LSAs.

2.   The OSPFv2 reserved address is represented in OSPFv2 by FF02::5, and the OSPFv2 reserved address is represented by FF02::6.

3.  You can use the IP address on the outside interface with PAT, Port Address Translation, but you shouldn't do so with either version of NAT.

4.  The wildcard mask is represented by the word "any".   With that wildcard mask, you literally have 32 "I don't care" bits.

5.  The hex value a4D breaks down to ...

10 units of 256  = 2560

4 units of 16 = 64

13 units of 1 = 13

... add 'em up and you have 2837!

See you tomorrow with five new CCNA and CCNP practice exam questions, and just maybe a new video or two!

Chris B.

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